X^2+21x+86=0

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Solution for X^2+21x+86=0 equation: 



X^2+21X+86=0

a = 1; b = 21; c = +86;
Δ = b2-4ac
Δ = 212-4·1·86
Δ = 97
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(21)-\sqrt{97}}{2*1}=\frac{-21-\sqrt{97}}{2}
$


$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(21)+\sqrt{97}}{2*1}=\frac{-21+\sqrt{97}}{2}
$

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